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April 29th, 2011, 03:16 PM   #1
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Permutation

Two families, each have a husband, a wife, two sons and a daughter, are planning to go to a baseball game and sit together in the same row.
In how many ways can they be seated if all the males are to sit together and all the females to sit together?

Males sitting together = 6! = 6*5*4*3*2*1 = 720
Females siting together = 4! = 4*3*2*1 = 24

Am i correct by saying this ??
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April 29th, 2011, 03:26 PM   #2
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Re: Permutation

Yes, also consider they may be arranged:

MMMMMMFFFF or FFFFMMMMMM
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April 29th, 2011, 03:32 PM   #3
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Re: Permutation

So how would i include them all together ... by adding the outcomes together ???

720+24 = 744

or

10*9*8*7*6*5*4*3*2*1 = 3628800
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April 29th, 2011, 03:38 PM   #4
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Re: Permutation

No, you multiply, then double for the two arrangements I gave above:

N = 2(6!4!) = 34560
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