My Math Forum Permutation

 Algebra Pre-Algebra and Basic Algebra Math Forum

 April 29th, 2011, 03:16 PM #1 Newbie   Joined: Apr 2011 Posts: 26 Thanks: 0 Permutation Two families, each have a husband, a wife, two sons and a daughter, are planning to go to a baseball game and sit together in the same row. In how many ways can they be seated if all the males are to sit together and all the females to sit together? Males sitting together = 6! = 6*5*4*3*2*1 = 720 Females siting together = 4! = 4*3*2*1 = 24 Am i correct by saying this ??
 April 29th, 2011, 03:26 PM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: Permutation Yes, also consider they may be arranged: MMMMMMFFFF or FFFFMMMMMM
 April 29th, 2011, 03:32 PM #3 Newbie   Joined: Apr 2011 Posts: 26 Thanks: 0 Re: Permutation So how would i include them all together ... by adding the outcomes together ??? 720+24 = 744 or 10*9*8*7*6*5*4*3*2*1 = 3628800
 April 29th, 2011, 03:38 PM #4 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: Permutation No, you multiply, then double for the two arrangements I gave above: N = 2(6!4!) = 34560

 Tags permutation

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post abramo_k Algebra 4 February 27th, 2013 12:11 PM kingkos Algebra 1 December 6th, 2012 12:39 PM panky Algebra 8 November 21st, 2011 11:11 PM cyt_91 Advanced Statistics 1 January 29th, 2010 09:12 AM cyt_91 Advanced Statistics 1 January 29th, 2010 07:16 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top