My Math Forum  

Go Back   My Math Forum > High School Math Forum > Algebra

Algebra Pre-Algebra and Basic Algebra Math Forum


Reply
 
LinkBack Thread Tools Display Modes
April 17th, 2011, 09:12 AM   #1
Member
 
Joined: Apr 2011

Posts: 46
Thanks: 0

quadratic equation

hi the equation is t^2 - 5t + 6 =0
I got (t-2)(t-3) factorizing
t-2=0 t-3=0
t=2 t= 3


then the second part of the question is by examining the sign of the discriminant b^2 - 4ac in the quadratic formula show that

x^2 +4x +5 =o has no real solutions

a=1 b=4 c=5

16-4(1)(5)=

4 so it has real solutions.


Can anyone tell if I went wrong anywhere?
daveyf is offline  
 
April 17th, 2011, 09:41 AM   #2
Senior Member
 
Joined: Nov 2010

Posts: 502
Thanks: 0

Re: quadratic equation

Quote:
Originally Posted by daveyf

16-4(1)(5)=4 so it has real solutions.

Can anyone tell if I went wrong anywhere?
16 - 4(1)(5) = -4. not 4. So it has no real solutions.
DLowry is offline  
April 17th, 2011, 12:51 PM   #3
Member
 
Joined: Apr 2011

Posts: 46
Thanks: 0

Re: quadratic equation

ah ya negative cheers
daveyf is offline  
April 17th, 2011, 03:34 PM   #4
Senior Member
 
Joined: Nov 2010

Posts: 502
Thanks: 0

Re: quadratic equation

No problem! Good luck.
DLowry is offline  
Reply

  My Math Forum > High School Math Forum > Algebra

Tags
equation, quadratic



Thread Tools
Display Modes


Similar Threads
Thread Thread Starter Forum Replies Last Post
quadratic equation Caithsith Algebra 3 June 19th, 2013 04:30 PM
Quadratic Equation sachinrajsharma Algebra 2 February 20th, 2013 10:45 AM
simplify equation to get a quadratic equation mich89 Algebra 3 January 9th, 2013 01:22 PM
quadratic equation panky Algebra 6 October 3rd, 2011 04:09 PM
quadratic equation Caithsith Elementary Math 0 December 31st, 1969 04:00 PM





Copyright © 2019 My Math Forum. All rights reserved.