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April 17th, 2011, 09:12 AM  #1 
Member Joined: Apr 2011 Posts: 46 Thanks: 0  quadratic equation
hi the equation is t^2  5t + 6 =0 I got (t2)(t3) factorizing t2=0 t3=0 t=2 t= 3 then the second part of the question is by examining the sign of the discriminant b^2  4ac in the quadratic formula show that x^2 +4x +5 =o has no real solutions a=1 b=4 c=5 164(1)(5)= 4 so it has real solutions. Can anyone tell if I went wrong anywhere? 
April 17th, 2011, 09:41 AM  #2  
Senior Member Joined: Nov 2010 Posts: 502 Thanks: 0  Re: quadratic equation Quote:
 
April 17th, 2011, 12:51 PM  #3 
Member Joined: Apr 2011 Posts: 46 Thanks: 0  Re: quadratic equation
ah ya negative cheers

April 17th, 2011, 03:34 PM  #4 
Senior Member Joined: Nov 2010 Posts: 502 Thanks: 0  Re: quadratic equation
No problem! Good luck.


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equation, quadratic 
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