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January 25th, 2011, 11:13 AM   #1
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Numerical result of the solve function

Seeking the common points to the parabola and the circle where the distance AB.


White not assume the function 'solve' the values of Xa, Za and AB in the equation and thus obtain a numerical result rather than analytical in the first call?


Xa=.5
Za=1
AB=1

%----------------------CÁLCULOS----------------------------------------------
% Za=1/(4*F)*Xa^2 - equation of the parabola that passes the point A(Xa,Za)
% Zb=1/(4*F)*Xb^2; - equation of the parabola that passes the point B(Xb,Zb)
% (Xb-Xa)^2+(Zb-Za)^2=AB^2 -equation of the circle of radius AB centered at the point A(Xa,Za)
%................................................. ...........................

% first call SOLVE
[F,Xb,Zb]=solve('1/(4*F)*Xa^2-Za','1/(4*F)*Xb^2-Zb','(Xb-Xa)^2+(Zb-Za)^2-AB^2');

% call SOLVE with the values of Xa,Za,AB the result are numeric
[F,Xb,Zb]=solve('1/(4*F)*[color=#FF0000].5[/color]^2-[color=#FF0000]1[/color]','1/(4*F)*Xb^2-Zb','(Xb-[color=#FF0000].5[/color])^2+(Zb-[color=#FF0000].5[/color])^2-[color=#FF0000]1[/color]^2');



appreciate any help

ahlf
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