 My Math Forum Exponential and Logarithmic functions and equations Part 2

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December 3rd, 2010, 11:30 AM   #1
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Exponential and Logarithmic functions and equations Part 2

Hi it's me again. This is part 2 of the pretest. ty

[attachment=3:9mhh7y0t]11.PNG[/attachment:9mhh7y0t]
11.
(8 x log 32/log 4 + 8 X log 8/log 2) – (log2 16)2
( 20 + 24 ) - (log2 16)2
44 – (log 16/log2)2
44 – (4)2
22 – 16
28

[attachment=2:9mhh7y0t]12.PNG[/attachment:9mhh7y0t]
12.
This I'm Totally lost on - how to do it?

[attachment=1:9mhh7y0t]13.PNG[/attachment:9mhh7y0t]
13.
I believe I know how to do this and will post it soon once I get time to wrap my mind around it. Feel free to solve it if you like. I'll do it myself also. ty

[attachment=0:9mhh7y0t]14.PNG[/attachment:9mhh7y0t]

14.
Attached Images 11.PNG (20.5 KB, 246 views) 12.PNG (54.4 KB, 246 views) 13.PNG (27.0 KB, 246 views) 14.PNG (88.0 KB, 246 views) December 3rd, 2010, 12:14 PM #2 Senior Member   Joined: Nov 2010 Posts: 288 Thanks: 1 Re: Exponential and Logarithmic functions and equations Part hello there u have amistake in question 11 the answer should be 16 notic that log 32 +log8 =log(32* =log 256=log4^4 since the base is 4 u get 4 so u have 8*4=32 now the other part is truly 16 so u have 32-16=16 December 3rd, 2010, 12:23 PM #3 Senior Member   Joined: Nov 2010 Posts: 288 Thanks: 1 Re: Exponential and Logarithmic functions and equations Part last question a: true loga+logb= loga*b this is arule in logarithm( u should make areview on the rules of logarithm) b:false: loga-logb=log(a/b) (this is another rule) so the answer should be log(x^2/y) c:false mlogn=logn^m not the other way (this is another rule) d:true e:false loga)^m is not equal to 3loga logmn)^3=(logmn)^3 this is the simplest form f:false the root should be inside the log meaning log root(c^2) :root i mean the third root December 3rd, 2010, 12:28 PM #4 Member   Joined: Nov 2009 Posts: 67 Thanks: 0 Re: Exponential and Logarithmic functions and equations Part Hi Bday, It might be useful to post these things one at a time so multiple helpers can jump on board. I'll pick 12A Simplify: December 3rd, 2010, 01:07 PM   #5
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Re: Exponential and Logarithmic functions and equations Part

Quote:
 Originally Posted by islam hello there u have amistake in question 11 the answer should be 16 notic that log 32 +log8 =log(32* =log 256=log4^4 since the base is 4 u get 4 so u have 8*4=32 now the other part is truly 16 so u have 32-16=16
The bases are different. Without using change of base formula.....

-(\log_216)^2=" /> December 3rd, 2010, 01:19 PM #6 Global Moderator   Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,948 Thanks: 1140 Math Focus: Elementary mathematics and beyond Re: Exponential and Logarithmic functions and equations Part 13A. -6 is no good! x = 3. December 3rd, 2010, 01:34 PM #7 Member   Joined: Nov 2009 Posts: 67 Thanks: 0 Re: Exponential and Logarithmic functions and equations Part 13B Disregard December 3rd, 2010, 01:54 PM #8 Senior Member   Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: Exponential and Logarithmic functions and equations Part For 12B, use: so that becomes If your book meant then we would have: December 3rd, 2010, 02:47 PM #9 Global Moderator   Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,948 Thanks: 1140 Math Focus: Elementary mathematics and beyond Re: Exponential and Logarithmic functions and equations Part Another look at 12A: December 3rd, 2010, 06:39 PM   #10
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Re: Exponential and Logarithmic functions and equations Part

Quote:
Originally Posted by masters
Quote:
 Originally Posted by islam hello there u have amistake in question 11 the answer should be 16 notic that log 32 +log8 =log(32* =log 256=log4^4 since the base is 4 u get 4 so u have 8*4=32 now the other part is truly 16 so u have 32-16=16
The bases are different. Without using change of base formula.....

-(\log_216)^2=" />

yes right sorry my mistake Tags equations, exponential, functions, logarithmic, part Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post shiseonji Algebra 1 September 18th, 2013 09:12 AM Francois Algebra 1 January 18th, 2013 08:25 AM mathstud Algebra 33 July 23rd, 2012 11:19 AM Bday Algebra 7 December 3rd, 2010 04:06 PM laceyf53 Algebra 1 March 16th, 2008 02:42 PM

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