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 November 29th, 2010, 10:41 AM #1 Newbie   Joined: Nov 2010 Posts: 3 Thanks: 0 Graphing Functions How would you go about solving these equations f(x)=2x^2 +1 find f(x+2)-[f(x)+2] f(x) = 2x+4 find f(3x) - 3f(x)
 November 29th, 2010, 12:53 PM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,155 Thanks: 466 Math Focus: Calculus/ODEs Re: Graphing Functions I would evaluate them algebraically rather than graphically. For the first one, if $f(x)=2x^2+1$ then $f(x+2)-(f(x)+2)=\left(2(x+2)^2+1\right)-\left(2x^2+1+2\right)=\left(2\left(x^2+4x+4\right) +1\right)-\left(2x^2+3\right)=$ $\left(2x^2+8x+9\right)-\left(2x^2+3\right)=8x+6$ For the second one, if $f(x)=2x+4$ then $f(3x)-3f(x)=(2(3x)+4)-3(2x+4)=(6x+4)-(6x+12)=-8$

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