My Math Forum Exponent Questions

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October 27th, 2010, 04:35 PM   #1
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Exponent Questions

1. If you had (2^6 ÷ 2^4)^3 would you first subtract the 2^6 ÷ 2^4 using exponent laws to equal (2^2)^3 or multiply the 3 by the other to powers to equal
2^18 ÷ 2^12. I know they both equal 2^6 but is there a certain way to start this?

2. Is there an exponent law if there is 2^12 + 2^6?

3. For the Img below. how can you simplify it further?

THX but now can someone help me w/ 3rd question now?
Attached Images
 Equation2.jpg (12.1 KB, 64 views)

 October 27th, 2010, 05:03 PM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: Exponent Questions Typically you begin inside the parentheses, but as you found they are equivalent. Just look to see whichever way makes it simpler to work out. For the second one, you can factor: $2^{12} + 2^6=2^6\left(2^6 + 1\right)$
 October 27th, 2010, 05:38 PM #3 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: Exponent Questions You have: $\dfrac{c^8}{3^2a^4b^6}$ Notice all of the exponents are factors of 2. Thus, we may write it as: $\left(\dfrac{c^4}{3a^2b^3}\right)^2$
October 27th, 2010, 06:49 PM   #4
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Re: Exponent Questions

Quote:
 Originally Posted by MarkFL You have: $\dfrac{c^8}{3^2a^4b^6}$ Notice all of the exponents are factors of 2. Thus, we may write it as: $\left(\dfrac{c^4}{3a^2b^3}\right)^2$

just that?

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