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September 26th, 2010, 10:51 AM  #1 
Member Joined: Sep 2008 Posts: 97 Thanks: 0  Factoring Polynomials:
I am just starting to learn about factoring polynomials and plugged this problem into mathway.com m(mn)2n(nm) I've figured out most of the steps but i'm having trouble with the final answer. "In this problem and 21=1, so insert 2 as the right hand term of one factor and 1 as the righthand term of the other factor. (m+2n)(mn)" This is as far as i've gotten: How do i get the final answer? Can someone explain it a little more? 
September 26th, 2010, 11:04 AM  #2 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,155 Thanks: 463 Math Focus: Calculus/ODEs  Re: Factoring Polynomials:
If you've got: m(m  n)  2n(n  m) and you want to factor it, use (m  n) = (n  m) to rewrite it as: m(m  n) + 2n(m  n) then, factor out the (m  n) common to both terms as follows: (m  n)(m + 2n) and it is now factored. 
September 26th, 2010, 01:55 PM  #3 
Member Joined: Sep 2008 Posts: 97 Thanks: 0  Re: Factoring Polynomials:
This is interesting. ... I think i'll try this one out on some of my problems. Thank you!


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