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September 15th, 2010, 05:43 AM   #1
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six digit numbers...

ok....here is a nice problem/brain teaser...:

How many six digit numbers can be formed such that the sum of the first three digits is equal to the sum of the last three digits???
(Leading zeros are not allowed, and the repetition of digits is allowed.)

HELP
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September 15th, 2010, 08:13 AM   #2
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50412 (of which 5856 have no repetition)
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September 15th, 2010, 08:55 AM   #3
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Re: six digit numbers...

I got 50413. Must have counted one twice...
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September 16th, 2010, 12:41 AM   #4
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Re: six digit numbers...

could you please explain a little ???
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September 16th, 2010, 01:47 PM   #5
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I checked each 6-digit integer.
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September 16th, 2010, 03:01 PM   #6
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Re:

Quote:
Originally Posted by skipjack
I checked each 6-digit integer.
And here I was, thinking you had no sense of humor ...
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