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September 15th, 2010, 05:43 AM  #1 
Newbie Joined: Jun 2009 Posts: 14 Thanks: 0  six digit numbers...
ok....here is a nice problem/brain teaser...: How many six digit numbers can be formed such that the sum of the first three digits is equal to the sum of the last three digits??? (Leading zeros are not allowed, and the repetition of digits is allowed.) HELP 
September 15th, 2010, 08:13 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 18,844 Thanks: 1566 
50412 (of which 5856 have no repetition)

September 15th, 2010, 08:55 AM  #3 
Global Moderator Joined: Nov 2009 From: Northwest Arkansas Posts: 2,766 Thanks: 4  Re: six digit numbers...
I got 50413. Must have counted one twice...

September 16th, 2010, 12:41 AM  #4 
Newbie Joined: Jun 2009 Posts: 14 Thanks: 0  Re: six digit numbers...
could you please explain a little ???

September 16th, 2010, 01:47 PM  #5 
Global Moderator Joined: Dec 2006 Posts: 18,844 Thanks: 1566 
I checked each 6digit integer.

September 16th, 2010, 03:01 PM  #6  
Global Moderator Joined: Nov 2009 From: Northwest Arkansas Posts: 2,766 Thanks: 4  Re: Quote:
 

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