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 August 19th, 2010, 01:58 AM #1 Member   Joined: Aug 2010 Posts: 35 Thanks: 0 hyperbola hi guys, I can't work out this question, could you please help with answer and explain? for what values of c is the (x,y) solution set of 2x^2 + cy^2 -1 = 0. thank you.
August 19th, 2010, 02:33 AM   #2
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Re: hyperbola

Quote:
 Originally Posted by mad hi guys, I can't work out this question, could you please help with answer and explain? for what values of c is the (x,y) solution set of 2x^2 + cy^2 -1 = 0. thank you.
The question is not clear. Can you elaborate further.

 August 19th, 2010, 02:37 AM #3 Member   Joined: Aug 2010 Posts: 35 Thanks: 0 Re: hyperbola sorry, for what values of c is the (x,y) solution set of 2x^2 + cy^2 -1 = 0 an hyperbola.
 August 19th, 2010, 05:44 AM #4 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: hyperbola What is the standard form for the equation of a hyperbola?
 August 20th, 2010, 01:28 AM #5 Member   Joined: Aug 2010 Posts: 35 Thanks: 0 Re: hyperbola x^2/a^2 - y^2/b^2 = 1. I spent hours trying, I'm not able to solve it.
 August 20th, 2010, 01:38 AM #6 Senior Member   Joined: Aug 2010 Posts: 109 Thanks: 0 Re: hyperbola Equation is not given to the hyperbola, but the ellipse
 August 20th, 2010, 01:43 AM #7 Senior Member   Joined: Aug 2010 Posts: 109 Thanks: 0 Re: hyperbola A = b = 2 because the ellipse-based and c = 2
August 20th, 2010, 01:50 AM   #8
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Re: hyperbola

Quote:
 Originally Posted by mad x^2/a^2 - y^2/b^2 = 1.
Looks like any negative c will do it.

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