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 July 18th, 2010, 03:40 PM #1 Newbie   Joined: Jul 2009 Posts: 12 Thanks: 0 How to find polar form and cartesian form of th...... Hi, Was wondering if I could get some insight on how to tackle this problem. [The problem is: "By Writing the complex numbers in polar form, $re^(^i^\ominus^)$, find a value for the quantity $(sqrt(3) +i)^{1/2}$. Give your answer in Cartesian form, $z= x+iy$ How would I find the R in this problem? In the back of the book, it says r is equal to square root of two To find r, I did the following thus far $sqrt(sqrt(3))^2 + 1= 2.73205......$then took square root of 2.73205 (used formula for a right hand triangle where x is $sqrt(sqrt(3)) and y is sqrt(1)$ help would be apreciated pleaseeeee
 July 18th, 2010, 05:52 PM #2 Member   Joined: Jun 2010 Posts: 36 Thanks: 0 Re: How to find polar form and cartesian form of th...... The given problem can be written as $(\sqrt{3} + 1)^{1/2}$ = $[2(\frac{\sqrt{3}}{2} + \frac{1}{2})]^{1/2}$ Now write the expression in the form of r(cos? +isin?)
July 18th, 2010, 06:05 PM   #3
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Re: How to find polar form and cartesian form of th......

Quote:
 Originally Posted by sa-ri-ga-ma The given problem can be written as $(\sqrt{3} + 1)^{1/2}$ = $[2(\frac{\sqrt{3}}{2} + \frac{1}{2})]^{1/2}$ Now write the expression in the form of r(cos? +isin?)
I'm sorry, but can you explain how it can be rewritten like that? I have no clue what you just did

 July 18th, 2010, 06:12 PM #4 Newbie   Joined: Jul 2009 Posts: 12 Thanks: 0 Re: How to find polar form and cartesian form of th...... I figured it out thanks for help

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