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July 9th, 2010, 04:31 PM  #1 
Member Joined: Apr 2010 Posts: 33 Thanks: 0  D=RT (Distance = Rate x Time)
[color=#FF0000]Here is the problem:[/color] Two birds start flying from the tops of two towers 50 ft apart at the same time and at the same rate. One tower is 30 ft high, and the other tower is 40 ft high. The birds reach a grass seed on the ground at exactly the same time. How far is the grass seed from the 40 foot tower? [color=#FF0000]I have absolutely no clue how to set up an equation for this problem. Can you please explain the equation you provide.[/color] 
July 9th, 2010, 05:31 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,629 Thanks: 2077 
If the seed lies directly between the towers and is x ft from the 40 ft tower and (50  x) ft form the 30 ft tower, and if each bird flies in a straight line to the seed, each flies the same distance. Using Pythagoras to give two expressions for the square of that distance you get the equation below. (50  x)² + 30² = x² + 40² 
July 9th, 2010, 06:18 PM  #3 
Member Joined: Apr 2010 Posts: 33 Thanks: 0  Re: D=RT (Distance = Rate x Time)
The book said the answer is 18 ft. The grass seed is 18 ft from the 40foot tower. I don't think your equation provides the same answer; But I think you still have to use the Pythagorean Theorem.

July 9th, 2010, 06:29 PM  #4  
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs  Re: D=RT (Distance = Rate x Time) Quote:
 
July 9th, 2010, 06:47 PM  #5 
Member Joined: Apr 2010 Posts: 33 Thanks: 0  Re: D=RT (Distance = Rate x Time)
Disregard what I just said about your equation being incorrect. It is correct; It was an error on my part.


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