My Math Forum D=RT (Distance = Rate x Time)

 Algebra Pre-Algebra and Basic Algebra Math Forum

 July 9th, 2010, 03:14 PM #1 Member   Joined: Apr 2010 Posts: 33 Thanks: 0 D=RT (Distance = Rate x Time) [color=#FF0000]Heres is the math problem:[/color] If a parade 2 mi long is proceeding at 3 mph, how long will it take a runner, jogging at 6 mph, to travel from the end of the parade to the start of the parade? [color=#FF0000]The book said the answer is 2/3 hr. Would the equation look like this: 6n - 3n = 2 If this is the correct way, can you make sense of it for me because I can't.[/color]
 July 9th, 2010, 03:31 PM #2 Guest   Joined: Posts: n/a Thanks: Re: D=RT (Distance = Rate x Time) Yeah, that formula look good. Think of it as the jogger running the same distance as the parade plus the 2 miles for the length of the parade. $6t=3t+2$ $6t-3t=2$ $t=\frac{2}{3}$ The jogger travels however far the parade travels plus the length of the parade. See now?.
 July 9th, 2010, 03:36 PM #3 Global Moderator   Joined: Dec 2006 Posts: 20,978 Thanks: 2229 The jogger's rate relative to the parade is 6mph - 3mph, i.e., 3mph, so time = distance / rate = 2 miles / 3 mph = 2/3 hr.
 July 9th, 2010, 03:42 PM #4 Member   Joined: Apr 2010 Posts: 33 Thanks: 0 Re: D=RT (Distance = Rate x Time) I get it now. Thanks you guys. I might post a similar problem later. I could use your help if I do

 Tags distance, drt, rate, time

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post HellBunny Algebra 3 August 16th, 2012 12:46 PM Mighty Mouse Jr Algebra 4 July 9th, 2010 06:47 PM Mighty Mouse Jr Algebra 4 June 29th, 2010 03:24 PM lak_ar Algebra 2 March 11th, 2008 12:09 PM marie789 Algebra 2 December 11th, 2007 08:13 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top