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July 9th, 2010, 03:14 PM  #1 
Member Joined: Apr 2010 Posts: 33 Thanks: 0  D=RT (Distance = Rate x Time)
[color=#FF0000]Heres is the math problem:[/color] If a parade 2 mi long is proceeding at 3 mph, how long will it take a runner, jogging at 6 mph, to travel from the end of the parade to the start of the parade? [color=#FF0000]The book said the answer is 2/3 hr. Would the equation look like this: 6n  3n = 2 If this is the correct way, can you make sense of it for me because I can't.[/color] 
July 9th, 2010, 03:31 PM  #2 
Guest Joined: Posts: n/a Thanks:  Re: D=RT (Distance = Rate x Time)
Yeah, that formula look good. Think of it as the jogger running the same distance as the parade plus the 2 miles for the length of the parade. The jogger travels however far the parade travels plus the length of the parade. See now?. 
July 9th, 2010, 03:36 PM  #3 
Global Moderator Joined: Dec 2006 Posts: 20,379 Thanks: 2011 
The jogger's rate relative to the parade is 6mph  3mph, i.e., 3mph, so time = distance / rate = 2 miles / 3 mph = 2/3 hr. 
July 9th, 2010, 03:42 PM  #4 
Member Joined: Apr 2010 Posts: 33 Thanks: 0  Re: D=RT (Distance = Rate x Time)
I get it now. Thanks you guys. I might post a similar problem later. I could use your help if I do 

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