July 5th, 2010, 09:59 AM  #1 
Newbie Joined: Jun 2010 Posts: 24 Thanks: 0  Proportion
I need a simple way to solve this question. It takes 3 men to dig 2 identical trenches in 5 hours. If all the men work at the same rate, how long will it take 5 men to dig 7 of these trenches? I have solved it this way through the help of an example in the book. Solution First we keep the number of trenches constant No of men  No of trenches  No of Hours 3  2  5 1  2  5*3 5  2  (5*3)/5=3 Next we keep the number of men constant No of men  No of trenches  No of Hours 5  2  3 5  1  3/2=1.5 5  7  1.5*7=10.5 Therefore 5 men will take 10.5 hours to dig 7 identical trenches. I want a simpler solution to this. 
July 5th, 2010, 10:23 AM  #2 
Math Team Joined: Apr 2010 Posts: 2,770 Thanks: 356  Re: Proportion
Hello Haftakan, is constant. In this case In this case. Will this do? Hoempa 
July 5th, 2010, 01:49 PM  #3 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,475 Thanks: 886 Math Focus: Elementary mathematics and beyond  Re: Proportion
(number of trenches per man per 5 hours) * (number of men) * (number of 5 hour periods) = (number of trenches) (2/3) * (5) * (x) = 7. 

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