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 June 15th, 2010, 04:10 AM #1 Newbie   Joined: Jun 2010 Posts: 1 Thanks: 0 Please Read! :) Math help D: I'm really on math help cause the teacher doesn't really letting us now about it T.T I'm on the back on class and I'm just turning 1st year 8P I really have a problem about the solution set T.T y+2<3 and I got this domain 1 1--- 2 I really need help I'm really interested in math this year more than last year v.v...
 June 15th, 2010, 04:14 AM #2 Math Team   Joined: Apr 2010 Posts: 2,778 Thanks: 361 Re: Please Read! :) Math help D: Hello ImSanta, It is you want to know for which y, y+2<3 is true? Hoempa
June 15th, 2010, 10:30 AM   #3
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Quote:
 Originally Posted by ImSanta I'm really on math help cause the teacher doesn't really letting us now about it T.T I'm on the back on class and I'm just turning 1st year 8P I really have a problem about the solution set T.T y+2<3 and I got this domain 1 1--- 2 I really need help I'm really interested in math this year more than last year v.v...

subtracting the two from both sides of the inequality gives:

$y < 1$

If by domain the question means all possible values of y, then it would be the greatest value of y is the repeating decimal:

GREATEST$\;\; y= 0.99999999999999999999999...........$

and the least possible value is negative infinity, since y only has to be less than 1. This could be the wrong answer if the domain in question is not the one I explained in my first sentence, I was not certain what is meant by domain. My apologies

 June 15th, 2010, 12:51 PM #4 Global Moderator   Joined: Dec 2006 Posts: 18,951 Thanks: 1599 Hi ImSanta, it seems you used division instead of subtraction. The domain could be given as {y|y < 1} or in certain other ways. Perhaps you've been taught to use some specific notation.
 June 15th, 2010, 01:39 PM #5 Senior Member   Joined: May 2008 From: York, UK Posts: 1,300 Thanks: 0 Re: Please Read! :) Math help D: mfetch22, you should note that the repeating decimal 0.9999... is actually equal to 1, and so does not lie in the set $\{y\,:\,y\,<\,1\}.$ This set has no greatest element - for any $y_0\in\{y\,:\,y\,<\,1\},$ there is an element $y_1\,>\,y_0$ with $y_1\in\{y\,:\,y\,<\,1\}.$
June 15th, 2010, 01:59 PM   #6
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 Originally Posted by mattpi mfetch22, you should note that the repeating decimal 0.9999... is actually equal to 1, and so does not lie in the set $\{y\,:\,y\,<\,1\}.$ This set has no greatest element - for any $y_0\in\{y\,:\,y\,<\,1\},$ there is an element $y_1\,>\,y_0$ with $y_1\in\{y\,:\,y\,<\,1\}.$
Thank you mattpi, I should have realized such a mistake. Set Theory is a much better manner in which to describe the bounds of this inequality, rather then attempting to slap a value on the maximum like I did. Good call, my mistake, thanks for catching it.

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