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June 13th, 2010, 07:07 PM   #1
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How are these the first three positive values of theta? (Inv

For the inverse function, arccos(4/5)=4(theta-40*), I have to find the three first positive values of theta. Simplified, I got the equations: 49.217+(?n/2) and 30.7825+(?n/2). Using these equations, I got the three positive values: 30.7823, 32.3533, and 49.2174. However, the book says the first three positive values are 30.7823* (got that one),49.2174*(got that one too), and 120.783* (didn't get this one).
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June 14th, 2010, 09:33 AM   #2
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Re: How are these the first three positive values of theta? (Inv

Hello, Noraowolf!

[color=red]skipjack is right . . . I blew it![/color]



Quote:


Find the first three positive values of

The answers are:[color=beige] .[/color]



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[color=beige]. . . . . . . . . . . . . [/color]

[color=beige]. . . . . . . . . . . . . . [/color]

[color=beige]. . . . . . . . . . . . . . [/color]




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June 14th, 2010, 11:10 AM   #3
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That is incorrect.





Hence the first few positive values are 30.7825, 49.2175, 120.7825 and 139.2175.
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