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June 13th, 2010, 07:07 PM  #1 
Newbie Joined: Jun 2010 Posts: 1 Thanks: 0  How are these the first three positive values of theta? (Inv
For the inverse function, arccos(4/5)=4(theta40*), I have to find the three first positive values of theta. Simplified, I got the equations: 49.217+(?n/2) and 30.7825+(?n/2). Using these equations, I got the three positive values: 30.7823, 32.3533, and 49.2174. However, the book says the first three positive values are 30.7823* (got that one),49.2174*(got that one too), and 120.783* (didn't get this one).

June 14th, 2010, 09:33 AM  #2  
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 408  Re: How are these the first three positive values of theta? (Inv Hello, Noraowolf! [color=red]skipjack is right . . . I blew it![/color] Quote:
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June 14th, 2010, 11:10 AM  #3 
Global Moderator Joined: Dec 2006 Posts: 20,927 Thanks: 2205 
That is incorrect. Hence the first few positive values are 30.7825°, 49.2175°, 120.7825° and 139.2175°. 

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