My Math Forum Logarithms

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 June 12th, 2010, 09:59 PM #1 Newbie   Joined: Jun 2010 Posts: 3 Thanks: 0 Logarithms According to the book, the answer is "2" Can anyone prove it?
 June 13th, 2010, 03:00 AM #2 Member   Joined: Jun 2010 Posts: 35 Thanks: 0 Re: Logarithms $\log_3 36-4\log_9 30 +16\log_{81} \sqrt15=$ $\log_3 3^2 +\log_3 4 - 2 \log_3 30+ 4\log_3 15^{1/2}=$ $2+\log_3 4 -2\log_3 15*2 + 2\log_3 15=$ $2+\log_3 4-2\log_3 15 - 2\log_3 2 + 2\log_3 15=$ $2+2\log_3 2 - 2\log_3 2=2$ I just did the maths actions without explaining, considering that you will know the steps that this exercise is going and if you don't understand anything feel free to ask. At the first line there is $\log \sqrt15$ with base 81 and not 8 like it is being showed. I tried to fix it but I couldn't. So I hope this will help.

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