
Algebra PreAlgebra and Basic Algebra Math Forum 
 LinkBack  Thread Tools  Display Modes 
October 1st, 2007, 11:52 AM  #1 
Newbie Joined: Oct 2007 Posts: 3 Thanks: 0  Yes, this may be an easy question, but im stumped
ok, so i've just entered college after taking a year off after high school. So I have COMPLETELY lost all my math skills.....so if you could run me throught the process of how to complete this question, it should clear up some of the others. Thanks! Simplify: (3/x) + [1/(x^2 + x)]  (1/x+1)  (1/x1) The answer in the book is : (3x+4)(x1)  2x 
October 1st, 2007, 02:35 PM  #2 
Senior Member Joined: Sep 2007 From: USA Posts: 349 Thanks: 67 Math Focus: Calculus 
For the denominator, do you mean 1/(x + 1)  1/(x  1) or 1/x + 1  1/x + 1?

October 1st, 2007, 02:37 PM  #3 
Newbie Joined: Oct 2007 Posts: 3 Thanks: 0 
1/(x + 1)  1/(x  1) sorry for the confusion 
October 1st, 2007, 03:02 PM  #4 
Senior Member Joined: Sep 2007 From: USA Posts: 349 Thanks: 67 Math Focus: Calculus 
What I would do is multiply the numerator and the denominator by (x+1)(x1), which would eliminate the fractions in the denominator. Then you can simplify the numerator.

October 1st, 2007, 03:15 PM  #5 
Newbie Joined: Oct 2007 Posts: 3 Thanks: 0 
i still dont understand how you can just multiply both denominator and numerator. both the numerator and denominator are fractions, so i dont understand how the process works.

October 1st, 2007, 03:32 PM  #6 
Senior Member Joined: Sep 2007 From: USA Posts: 349 Thanks: 67 Math Focus: Calculus 
Doing this is multiplying by 1, because (x+1)(x1)/[(x+1)(x1)]=1. For the numerator, you distribute (x+1)(x1) across the terms. You do the same for the denominator. [3/x + 1/(x(x+1))](x+1)(x1)  [1/(x+1)  1/(x1)](x+1)(x1) 3(x+1)(x1)/x + (x1)/x  (x1)  (x+1) (3x^2+x4)  2x (3x+4)(x1)  2x 

Tags 
easy, question, stumped 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Hopefully a v. easy question...  rebell1on  Algebra  3  February 8th, 2013 04:07 PM 
Very easy question but I can't see it.  perla  Algebra  2  August 27th, 2011 12:43 PM 
Easy question  studentx  Abstract Algebra  2  December 8th, 2010 04:13 AM 
easy question  football  Algebra  1  April 11th, 2010 03:51 AM 
easy question  wannabe1  Advanced Statistics  4  March 21st, 2010 03:41 PM 