My Math Forum find unique n number combination in total n number

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 May 17th, 2010, 06:21 PM #1 Newbie   Joined: May 2010 Posts: 2 Thanks: 0 find unique n number combination in total n number Hi all, I have a math question related to my programming problem. It is best to describe in scenario: find all possible x digit number in range(1 to y) (no-repeat) find all possible 1 digit number in 1-6 (no-repeat) answer = 1,2,3,4,5,6 find all possible 2 digit number in 1-6 (no repeat) (eg. 12, and 21 are the same) answer = 12,13,14,15,16 = 23,24,25,26 = 34,35,36 = 45,46 = 56 find all possible 3 digit number in 1-6 (no repeat) (eg, 123 and 321 are the same) answer = 123, 234, ... and so on I'm stuck in these, I need to come out with a formula as the x and y can be plug in Any help will be much appreciated! Thanks in advance
 May 17th, 2010, 07:26 PM #2 Global Moderator     Joined: Nov 2009 From: Northwest Arkansas Posts: 2,766 Thanks: 4 Re: find unique n number combination in total n number The number is the binomial coefficient. (http://en.wikipedia.org/wiki/Binomial_coefficient) To find all of the possible x-digit numbers would (obviously) require an algorithm. What have you tried?
May 18th, 2010, 04:39 AM   #3
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Re: find unique n number combination in total n number

Quote:
 Originally Posted by The Chaz The number is the binomial coefficient. (http://en.wikipedia.org/wiki/Binomial_coefficient) To find all of the possible x-digit numbers would (obviously) require an algorithm. What have you tried?
Does not look like that, anyway I've found the solution perhaps it can help others

http://www.sonyjose.in/blog/?p=62

 May 18th, 2010, 05:01 PM #4 Member   Joined: Apr 2010 Posts: 65 Thanks: 0 Re: find unique n number combination in total n number PARI/GP Code: f(c,z,b,n,k)={ if(z

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### all possible 123 number digit repeating combination

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