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 April 17th, 2010, 04:05 AM #1 Newbie   Joined: Apr 2010 Posts: 1 Thanks: 0 can somebody help me with this math problem?
 April 17th, 2010, 07:00 AM #2 Newbie   Joined: Apr 2010 Posts: 13 Thanks: 0 Re: can somebody help me with this math problem? So the 2nd part can be written as (1200/0.017)*(1.017^n - 1) expand it to get (1200/0.017)(1.017^n) - 1200/0.017 move the -1200/0.017 to the other side of the equal sign and with some factoring you will get 1200/0.017 = (1.017^n)*(16160.35 - 1200/0.017) isolate 1.017^n on one side of the equation. Use logarithm to solve and I think you will get an answer.
April 17th, 2010, 11:37 AM   #3
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Re: can somebody help me with this math problem?

Hello, mathstudent!

Quote:
 $16,160.35(1.017^n) \,-\,1200\,\frac{1.017^n\,-\,1}{0.017} \;=\;0$

$\text{Multiply by 0.017:\;\;274.72595(1.017^n) \,-\,1200\(1.017^n) \,+\,1200 \;=\;0$

[color=beige]. . . [/color]$-925.27405(1.017^n) \;=\;-1200 \;\;\;\Rightarrow\;\;\;1.017^n \:=\:1.206913061$

$\text{Take logs: }\;\ln(1.017^n) \;=\;\ln(1.206913061) \;\;\;\Rightarrow\;\;\;n\,\cdot\,\ln(1.017) \:=\:\ln(1.296913061)$

$\text{Therefore: }\;n \;=\;\frac{\ln(1.296913061)}{\ln(1.017)} \;=\;15.42297362\,\cdots$

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