April 11th, 2010, 11:35 PM  #1 
Newbie Joined: Jan 2010 Posts: 20 Thanks: 0  solution
Hello everyone! I'm new to this site and have a doubt. 1. x squared minus 92y squared =1 Please reply as I don't know latex 
April 12th, 2010, 02:27 AM  #2 
Math Team Joined: Apr 2010 Posts: 2,778 Thanks: 361  Re: solution
Hello bentick, What do you mean? or x^2(92y)^2=1 Hoempa 
April 12th, 2010, 03:08 AM  #3  
Senior Member Joined: Mar 2009 Posts: 318 Thanks: 0  Quote:
Quote:
Please be complete. Thank you!  
April 12th, 2010, 01:05 PM  #4 
Global Moderator Joined: Dec 2006 Posts: 18,034 Thanks: 1393 
There are solutions such as x = 1, y = 0.

April 12th, 2010, 10:05 PM  #5 
Newbie Joined: Jan 2010 Posts: 20 Thanks: 0  Re: solution
Please solve this equation. IE. Solve for the value of x and y. According to me, as I have solved it x^2 92y^2=1 x^2 =1+92y^2 then substitute the value of x^2. If it is solved by substituting then the answer comes as 1=1 Is this correct? 
April 13th, 2010, 10:22 AM  #6  
Senior Member Joined: Mar 2009 Posts: 318 Thanks: 0  Re: solution Quote:
Since you have only one equation but two unknowns, there is no way to find "the" solution, only many solutions or the graph.  
April 13th, 2010, 01:27 PM  #7 
Global Moderator Joined: Dec 2006 Posts: 18,034 Thanks: 1393 
Are x and y required to be integers? If so, are they required to be positive integers?

April 14th, 2010, 01:25 AM  #8 
Newbie Joined: Jan 2010 Posts: 20 Thanks: 0  Re: solution
@skipjack I don't know about that. My question is this solvable than the other solution I posted, if so please reply 
April 14th, 2010, 04:33 AM  #9 
Global Moderator Joined: Dec 2006 Posts: 18,034 Thanks: 1393 
You hadn't previously asked whether the equation can be solved. Instead, you said that the task was to solve for both x and y, which disallows your suggested substitution (since it would need the value of x² to be known in advance). As is stands, the equation has infinitely many real solutions, and infinitely many complex solutions that are not real. However, this type of equation is often set in a context that implies that only integer solutions are sought, which is why I asked about that. There are infinitely many solutions in positive integers, but I suspect you haven't been taught how to find them. Do any of your textbooks even mention Diophantine equations? 
April 14th, 2010, 10:06 PM  #10 
Newbie Joined: Jan 2010 Posts: 20 Thanks: 0  Re: solution
@skipjack I'm going to 9th grade this year. @skipjack no my text books doesn't mention anything like Diophantine equations. I just came across this question. But now I got to know the answer : IE. there are infinite solutions. I found the values for x,y too. x=1, y=0 or x=1151, y=120 

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