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April 7th, 2010, 08:27 PM   #1
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Circle equation

I have to find the equation of the tangent to the circle with equation x^2 + y^2 = 8 at the point (2,-2)

I'm just not sure how to use the point to form the equation, please help and in advance many thanks for your time and effort.
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April 8th, 2010, 04:46 AM   #2
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Re: Circle equation

One of the standard forms for a straight line is the point-slope form. To use this form you need to know a point on the line and the slope of the line. You have a point. To get the slope, notice where the point (2,-2) is located. You should be able to get a slope for a radius of the circle and from that you can get the slope of the line you want.

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