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February 9th, 2010, 10:06 AM   #1
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Minimum value?

Hey, how would I algebraically find the minimum value of...say... ?
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February 9th, 2010, 01:10 PM   #2
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Re: Minimum value?

If you differentiate your function, you will get:

y= 1/2 * (x2 +(x-1)2)**(-1/2) * (2x+2(x-1)),

you can consider this as a product of two terms, the first one is always positive, a you are adding two positive numbers, so no minimum will came from here.
the second terms has a possible solution: 4x-2=0 ==> x = 1/2
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February 9th, 2010, 03:33 PM   #3
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y = x + (x - 1) = 2(x - 1/2) + 1/2, so the minimum value of y is ?(1/2).
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