February 9th, 2010, 10:06 AM  #1 
Newbie Joined: May 2008 Posts: 11 Thanks: 0  Minimum value?
Hey, how would I algebraically find the minimum value of...say... ?

February 9th, 2010, 01:10 PM  #2 
Newbie Joined: Dec 2009 Posts: 7 Thanks: 0  Re: Minimum value?
If you differentiate your function, you will get: y´= 1/2 * (x2 +(x1)2)**(1/2) * (2x+2(x1)), you can consider this as a product of two terms, the first one is always positive, a you are adding two positive numbers, so no minimum will came from here. the second terms has a possible solution: 4x2=0 ==> x = 1/2 
February 9th, 2010, 03:33 PM  #3 
Global Moderator Joined: Dec 2006 Posts: 20,747 Thanks: 2133 
y² = x² + (x  1)² = 2(x  1/2)² + 1/2, so the minimum value of y is ?(1/2).


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