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February 5th, 2010, 04:25 AM   #1
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A * 2^n = B, solving for n

I have a problem which seemed easy enough, but I which found difficult to solve.

I have two variables, A => B. I need to know how many times (n) you need to double A to get B, that is I need to find n for:

A * 2^n = B

Since I don't know what kind of math I need to solve this, I didn't know in which forum to post this thread. Sorry if this is the wrong place.

Thanks
/Göran
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February 5th, 2010, 06:19 AM   #2
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Re: A * 2^n = B, solving for n

You need logarithms:



Have a look at:
http://www.purplemath.com/modules/logs.htm
http://www.math.utah.edu/~pa/math/log.html
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February 5th, 2010, 07:55 AM   #3
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Re: A * 2^n = B, solving for n

Thanks! Works perfectly, will read up on the subject.
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