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 Algebra Pre-Algebra and Basic Algebra Math Forum

 January 28th, 2010, 12:04 AM #1 Member   Joined: Nov 2009 Posts: 49 Thanks: 0 what the hell do I do Can someone please explain to me what this question wants? "The sum of the first n natural numbers is equal to the sum of two quantities, the first of which is proportional to n and the second to n2. Work out the sums of the first three and four natural numbers and hence find the formula for the sum of the first n natural numbers." January 28th, 2010, 04:54 AM #2 Senior Member   Joined: Feb 2009 From: Adelaide, Australia Posts: 1,519 Thanks: 3 Re: what the hell do I do There are two numbers x and y such that, for all whole numbers n, 1+2+3+4+5+...+n = x(n�)+y(n) Now what you're supposed to do is say 1+2+3 = 6, therefore 6 = x(3�)+y(3) = 9x+3y 1+2+3+4 = 10, therefore 10 = x(4�)+y(4) = 16x+4y So you have 9x+3y=6 and 16x+4y=10, which you must solve for x and y. Tags hell Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post MasterOfDisaster Real Analysis 19 December 16th, 2015 11:22 PM jackregan Algebra 2 October 28th, 2013 05:08 AM mathwiz123 Calculus 2 December 12th, 2007 05:43 AM MasterOfDisaster New Users 1 December 31st, 1969 04:00 PM

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