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 August 21st, 2007, 02:20 PM #1 Senior Member   Joined: Dec 2006 From: New Jersey Posts: 378 Thanks: 1 Complete the Square When I complete the square of 3x^2 - 4x + 2 = 0, I get a totally different answer than when solving it using the quadratic formula. Can anyone here solve this using completing the square and show me step by step? The answer is: x = (2 + sqrt{2}i)/3 and x = (2 - sqrt{2}i)/3 Also, does it matter if I place the i before the square root symbol or after? In other words, should it be (sqrt{2}i) or i(sqrt{2}) for the question above?
 August 21st, 2007, 05:34 PM #2 Senior Member   Joined: Apr 2007 Posts: 2,140 Thanks: 0 Re: Complete the Square 0=3x^2-4x+2 0=x^2-(4/3)x+(2/3) 0=(x-(2/3))^2+(2/9) (-2/9)=(x-(2/3))^2 ±?(-2/9)=x-(2/3) ±?(-2/9)+(2/3)=x Therefore, we get.. x=(2±?(2)i)/3. You always put the number before an variable.

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