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December 17th, 2009, 12:56 AM  #1 
Newbie Joined: Dec 2009 Posts: 3 Thanks: 0  Find points on a line of equal distance from certain point
Hi Gents, We have line L1: 3 X + 4 Y + 12 = 0 I got the Xintercept (M) (4,0) Yintercept (A) (0,3) Distance (d) between A and M (d=4) Then I got line, L2, which is perpendiclar to L1 through M L2: 3 Y = 4 X +16 Anyone can confirm answers? THEN I STUCK ON:  Finding 2 points B & C on L2 whose distance from A = d* sq. root of 2 (d ?2)  Finding a point D that makes ABCD a square Thanks alot 
December 17th, 2009, 08:23 AM  #2 
Senior Member Joined: Dec 2009 From: Las Vegas Posts: 209 Thanks: 0  Re: Find points on a line of equal distance from certain point
Hi horees; A) is correct M) is correct d is not correct, the distance between A and M is 5 L2 is correct. The 2 points you want that are 5 sqrt(2) away from (0,3) and on L2 are (7,4) and (1,4) 
December 18th, 2009, 10:39 AM  #3 
Newbie Joined: Dec 2009 Posts: 3 Thanks: 0  Re: Find points on a line of equal distance from certain point
how u got (7,4) & (1,4)???

December 18th, 2009, 01:22 PM  #4 
Senior Member Joined: Dec 2009 From: Las Vegas Posts: 209 Thanks: 0  Re: Find points on a line of equal distance from certain point
Hi horees; I would be glad to. Here is how I did it. It is a little long and tedious. I will provide the overview and you can ask me for a further explanation if you want it. Here is how I got the distance from A to M. This is how I found the 2 points that are on L2 and that are 5 sqrt(2) away from (0,3) By squaring both sides the above equation becomes a quadratic with x =  1 and x =  7. Substituting for both x's into L2: So the points are (7,4) and (1, 4) 

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