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Find intersection of a Circle with Y-axis...Please find the equation of circle, C1: x2 + y2 + 4 x - 6y - 3 = 0 It has centre (-2,3) & Radius = 4 Hence, I need to find the intersection of the circle with Y-axis in 2 points A and B Then to find the point D of intersection of the tangent line to the circle @ A and B Thank you in Advance |

Re: Find intersection of a Circle with Y-axis... |

Re: Find intersection of a Circle with Y-axis...In this problem, the intersection with the axis Oy, is found by using itīs equation (Oy): x=0. Solving the system defined by both equations will give you the points A(0,a) and B(0,b), a and b will be the solutions to y2-6y-3=0. At this time, you can also calculate the tangents on both of these points, but their intersection should be at y=3, can you see why? Solving the equation y = (6 +-sqr(6*6-4(-3))/2= 3 +- sqr48/2= 3 +- sqr12 = 3 +-2sqr3 Then a = 3+2sqr3 and b = 3-2sqr3. |

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