My Math Forum anyone up for this matrix?

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 December 8th, 2009, 08:51 PM #1 Member   Joined: Oct 2009 Posts: 98 Thanks: 0 anyone up for this matrix? here it is. [2,5,-3=4] [4,-3,2=9] [5,6,-2=18] 4 columns, 3 rows, 3 variables left to right xyz I've tried a couple operations to this matrix, however to get it into (reduced) echelon form is difficult. It was a sad attempt. I've only got a zero in column 1 row 2 and 3. I would write out everything I've tried, but I don't have the time right now. It would take pretty long. I am asked to find all the solutions to the system. so there should be 3 solutions: x,y, and z? I would think? also some of the operations I did ended up turning most of the matrix into fractions, which I am not very familiar with dealing with in matrices
 December 8th, 2009, 09:03 PM #2 Global Moderator     Joined: Nov 2009 From: Northwest Arkansas Posts: 2,766 Thanks: 4 Re: anyone up for this matrix? Why did you quit? With a zero in (2,1) and (3,1), you are ready to move to the next column! This system/matrix represents 3 equations with three unknowns. You can call them x,y,z or x1, x2, x3 or whatever. Your goal is to reduce to matrix to 100 010 001 on the left and x y z on the right. If you have a graphing calculator, there are ways to check you work with minimal effort. Otherwise, you should Google "gauss-jordan elimination"! !!!!!!!!!!!!!!!!

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