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December 8th, 2009, 07:51 PM   #1
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anyone up for this matrix?

here it is.

[2,5,-3=4]
[4,-3,2=9]
[5,6,-2=18]


4 columns, 3 rows, 3 variables left to right xyz

I've tried a couple operations to this matrix, however to get it into (reduced) echelon form is difficult. It was a sad attempt. I've only got a zero in column 1 row 2 and 3.

I would write out everything I've tried, but I don't have the time right now. It would take pretty long. I am asked to find all the solutions to the system.

so there should be 3 solutions: x,y, and z? I would think? also some of the operations I did ended up turning most of the matrix into fractions, which I am not very familiar with dealing with in matrices
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December 8th, 2009, 08:03 PM   #2
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Re: anyone up for this matrix?

Why did you quit?
With a zero in (2,1) and (3,1), you are ready to move to the next column!

This system/matrix represents 3 equations with three unknowns. You can call them x,y,z or x1, x2, x3 or whatever.
Your goal is to reduce to matrix to
100
010
001
on the left and
x
y
z
on the right.
If you have a graphing calculator, there are ways to check you work with minimal effort.
Otherwise, you should Google "gauss-jordan elimination"! !!!!!!!!!!!!!!!!
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