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December 8th, 2009, 08:51 PM   #1
Joined: Oct 2009

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anyone up for this matrix?

here it is.


4 columns, 3 rows, 3 variables left to right xyz

I've tried a couple operations to this matrix, however to get it into (reduced) echelon form is difficult. It was a sad attempt. I've only got a zero in column 1 row 2 and 3.

I would write out everything I've tried, but I don't have the time right now. It would take pretty long. I am asked to find all the solutions to the system.

so there should be 3 solutions: x,y, and z? I would think? also some of the operations I did ended up turning most of the matrix into fractions, which I am not very familiar with dealing with in matrices
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December 8th, 2009, 09:03 PM   #2
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Re: anyone up for this matrix?

Why did you quit?
With a zero in (2,1) and (3,1), you are ready to move to the next column!

This system/matrix represents 3 equations with three unknowns. You can call them x,y,z or x1, x2, x3 or whatever.
Your goal is to reduce to matrix to
on the left and
on the right.
If you have a graphing calculator, there are ways to check you work with minimal effort.
Otherwise, you should Google "gauss-jordan elimination"! !!!!!!!!!!!!!!!!
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