My Math Forum Square Root and Square Problem

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 August 7th, 2007, 08:46 PM #1 Newbie   Joined: Aug 2007 Posts: 1 Thanks: 0 Square Root and Square Problem I stumbled upon the fact that this equation is true: n² / (√n * n) = √n But for the life of me, I cannot comprehend why. Maybe if I wrote it in a different way I would be able to see the relationship between the integers better, but my small brain cannot understand why this works Any help? Last edited by skipjack; June 23rd, 2015 at 02:10 PM.
 August 7th, 2007, 09:02 PM #2 Senior Member   Joined: Apr 2007 Posts: 2,140 Thanks: 0 i. √n * n ≠ 0 ii. n^(1/2+1) = n^3/2 ≠ 0 iii. n ≠ 0^2/3 iv. n² / (√n * n) = n^(2-(1/2)-1) = n^1/2
 August 8th, 2007, 04:39 AM #3 Senior Member   Joined: Dec 2006 Posts: 1,111 Thanks: 0 n² / (√n * n) = n² / (n^(1.5)) = n^(0.5) = √n
 August 8th, 2007, 09:06 AM #4 Global Moderator     Joined: Nov 2006 From: UTC -5 Posts: 16,046 Thanks: 938 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms √n is just n raised to the power of 1/2. √n times n is just n raised to the power of 1.5 = 1/2 + 1. n raised to power of 2 divided by n raised to the power of 1.5 is n raised to the power of 0.5 = 2 - 1.5. This is just √n. All this assumes, of course, that n > 0.

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