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August 7th, 2007, 09:46 PM   #1
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Square Root and Square Problem

I stumbled upon the fact that this equation is true:

n² / (√n * n) = √n

But for the life of me, I cannot comprehend why. Maybe if I wrote it in a different way I would be able to see the relationship between the integers better, but my small brain cannot understand why this works

Any help?

Last edited by skipjack; June 23rd, 2015 at 03:10 PM.
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August 7th, 2007, 10:02 PM   #2
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i. √n * n ≠ 0
ii. n^(1/2+1) = n^3/2 ≠ 0
iii. n ≠ 0^2/3
iv. n² / (√n * n) = n^(2-(1/2)-1) = n^1/2
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August 8th, 2007, 05:39 AM   #3
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n² / (√n * n) = n² / (n^(1.5)) = n^(0.5) = √n
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August 8th, 2007, 10:06 AM   #4
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√n is just n raised to the power of 1/2. √n times n is just n raised to the power of 1.5 = 1/2 + 1. n raised to power of 2 divided by n raised to the power of 1.5 is n raised to the power of 0.5 = 2 - 1.5. This is just √n.

All this assumes, of course, that n > 0.
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