
Advanced Statistics Advanced Probability and Statistics Math Forum 
 LinkBack  Thread Tools  Display Modes 
February 7th, 2014, 03:28 PM  #1 
Newbie Joined: Feb 2014 Posts: 2 Thanks: 0  probability problem in hexagon
So say I have 6 bugs standing on the 6 vertices of a hexagon, one per vertex. And say they each pick a vertex that they are not currently on, and starts moving in a straight line towards that vertex at the same speed. So my question is how many possibilities are there for the bugs to move to the vertices such that none of them are ever in the same place at the same time?

February 7th, 2014, 03:51 PM  #2 
Senior Member Joined: Oct 2013 From: New York, USA Posts: 664 Thanks: 87  Re: probability problem in hexagon
This seems like it should simply be 6! = 720 (719 other than the starting position).

February 7th, 2014, 04:01 PM  #3 
Newbie Joined: Feb 2014 Posts: 2 Thanks: 0  Re: probability problem in hexagon
I don't think so. No lines can intersect with another line at a point that is the same distance away from both starting vertices, so I think there are less.

February 8th, 2014, 06:43 AM  #4  
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 408  Re: probability problem in hexagon Hello, leuler! Quote:
The answer seems to be the number of derangements of 6 objects: But you remind us that the bugs must not collide . . . ack!  

Tags 
hexagon, probability, problem 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
hexagon  gaussrelatz  Algebra  3  April 14th, 2012 08:37 PM 
hexagon  e81  Algebra  2  May 17th, 2011 10:15 PM 
Hexagon  Rekooo  Algebra  1  December 19th, 2010 06:26 AM 
Help on Circum/inscribed Hexagon Problem  Hangman  Algebra  3  April 8th, 2009 04:28 AM 
Hexagon  teixeira  Algebra  7  September 27th, 2007 01:36 PM 