My Math Forum Chebychev, where mean is not in the middle of the estimated interval

 December 15th, 2016, 01:31 PM #1 Newbie   Joined: Dec 2016 From: Trinidad and Tobago Posts: 5 Thanks: 0 Chebychev, where mean is not in the middle of the estimated interval One more question, can you maybe help me again? Fifty-five percent of all students on a campus are in Humanities. If 150 students are selected at random, what is the probability that the proportion of Humanities students in this particular sample will be between 45% and 55%. I did the following 150*0.55=82.5 150*0.45=67.5 P(67.5
 December 15th, 2016, 01:54 PM #2 Global Moderator   Joined: May 2007 Posts: 6,398 Thanks: 546 15=kσ Where did 15 come from? What is k supposed to be?
 December 15th, 2016, 02:01 PM #3 Newbie   Joined: Dec 2016 From: Trinidad and Tobago Posts: 5 Thanks: 0 I posted the whole question. That's all that was given. 15 is 82.5-67.5 Therefore the interval I want to calculate. And if I understood it correctly That distance (15) equals kσ 15=kσ k=15/σ k=15/√σ² k=15/√37.25 k=0.1654 As I already stated. The Problem I'm having is that the mean is not in the middle of the interval. If it would be in the middle it would result in 7.5=kq. However I'm not sure whether I understood it correctly. Last edited by skipjack; December 15th, 2016 at 04:18 PM.

 Tags chebychev, estimated, interval, middle

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post yeaho26 Advanced Statistics 2 December 15th, 2016 01:02 PM jaredbeach Calculus 9 January 12th, 2012 09:49 PM Anton29 Advanced Statistics 18 December 5th, 2011 06:01 PM steve123 Advanced Statistics 2 August 1st, 2010 07:28 PM billy Linear Algebra 0 April 28th, 2010 07:40 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top