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February 28th, 2016, 11:53 AM  #1 
Newbie Joined: Feb 2016 From: Germany Posts: 1 Thanks: 0  continued fraction expansion of the complementary error function
Could someone please explain to a nonmathematician why the continued fraction expansion of the complementary error function is the following: How does one come to this fraction as conclusion? I know and understand this term of the error function: I also know that erfc(z) = 1  erf(z). 
February 28th, 2016, 01:39 PM  #2 
Global Moderator Joined: May 2007 Posts: 6,446 Thanks: 565  https://en.wikipedia.org/wiki/Error_function It will require a little work. Above has a section giving the continued fraction with a reference to a book containing its derivation. The book is available at various libraries throughout the world. 

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complementary, continued, error, expansion, fraction, function 
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