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February 28th, 2016, 11:53 AM   #1
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continued fraction expansion of the complementary error function

Could someone please explain to a non-mathematician why the continued fraction expansion of the complementary error function is the following:


How does one come to this fraction as conclusion?

I know and understand this term of the error function:

I also know that erfc(z) = 1 - erf(z).
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February 28th, 2016, 01:39 PM   #2
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https://en.wikipedia.org/wiki/Error_function

It will require a little work. Above has a section giving the continued fraction with a reference to a book containing its derivation. The book is available at various libraries throughout the world.
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