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October 8th, 2012, 01:09 AM  #11 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 520 Math Focus: Calculus/ODEs  Re: The Probability That Exactly One Of The Four Balls Is Wh
Please don't spam our forum with commercial links. I removed your post with the link, and left your question. Questions are fine, although you should begin your own topic.

October 9th, 2012, 11:41 AM  #12 
Senior Member Joined: Jan 2012 Posts: 741 Thanks: 7  Re: The Probability That Exactly One Of The Four Balls Is Wh
Let me go back to drawing board using the actual number of marbles this time without reducing any fraction to the lowest term. From the first bag P(w) = 12/20 P(b) = 8/20 From the second bag p(w) = 10/25 p(b) = 15/25 Bag 1 Bag 2  case1bw  bb  case2wb  bb  case3bb  wb  case4bb  bw  I think have to reduce the fraction where possible to make it easier for further simplification. In case 1 we have 8/20*12/19*15/25*14/24 = 2/5*12/19*3/5*7/12 = 504/5700 = 42/475 In case 2 we have 12/20*8/19*15/25*14/24 = 3/5*8/19*3/5*7/12 = 504/5700 = 42/475 In case 3 we have 8/20*7/19*10/25*15/24 = 2/5*7/19*2/5*15/24 420/11400 = 7/190 In case 4 we have 8/20*7/19*15/25*10/24 = 2/5*7/19*3/5*5/12 = 210/5700 = 7/190 Probability of getting excatly one white will now become (84+84+35+35)/950 = 238/950 = 119/475 = 0.251 I hope this one is better now? = 

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