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October 8th, 2012, 01:09 AM   #11
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Re: The Probability That Exactly One Of The Four Balls Is Wh

Please don't spam our forum with commercial links. I removed your post with the link, and left your question. Questions are fine, although you should begin your own topic.
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October 9th, 2012, 11:41 AM   #12
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Re: The Probability That Exactly One Of The Four Balls Is Wh

Let me go back to drawing board using the actual number of marbles this time without reducing any fraction to the lowest term.

From the first bag
P(w) = 12/20
P(b) = 8/20
From the second bag
p(w) = 10/25
p(b) = 15/25

|Bag 1| Bag 2 |
case1|bw | bb |
case2|wb | bb |
case3|bb | wb |
case4|bb | bw |

I think have to reduce the fraction where possible to make it easier for further simplification.
In case 1 we have
8/20*12/19*15/25*14/24
= 2/5*12/19*3/5*7/12
= 504/5700 = 42/475

In case 2 we have
12/20*8/19*15/25*14/24
= 3/5*8/19*3/5*7/12
= 504/5700
= 42/475

In case 3 we have
8/20*7/19*10/25*15/24
= 2/5*7/19*2/5*15/24
420/11400 = 7/190

In case 4 we have
8/20*7/19*15/25*10/24
= 2/5*7/19*3/5*5/12
= 210/5700 = 7/190
Probability of getting excatly one white will now become
(84+84+35+35)/950
= 238/950
= 119/475
= 0.251
I hope this one is better now?
=
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