My Math Forum The Probability That Exactly One Of The Four Balls Is White
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 October 8th, 2012, 01:09 AM #11 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: The Probability That Exactly One Of The Four Balls Is Wh Please don't spam our forum with commercial links. I removed your post with the link, and left your question. Questions are fine, although you should begin your own topic.
 October 9th, 2012, 11:41 AM #12 Senior Member     Joined: Jan 2012 Posts: 745 Thanks: 7 Re: The Probability That Exactly One Of The Four Balls Is Wh Let me go back to drawing board using the actual number of marbles this time without reducing any fraction to the lowest term. From the first bag P(w) = 12/20 P(b) = 8/20 From the second bag p(w) = 10/25 p(b) = 15/25 |Bag 1| Bag 2 | case1|bw | bb | case2|wb | bb | case3|bb | wb | case4|bb | bw | I think have to reduce the fraction where possible to make it easier for further simplification. In case 1 we have 8/20*12/19*15/25*14/24 = 2/5*12/19*3/5*7/12 = 504/5700 = 42/475 In case 2 we have 12/20*8/19*15/25*14/24 = 3/5*8/19*3/5*7/12 = 504/5700 = 42/475 In case 3 we have 8/20*7/19*10/25*15/24 = 2/5*7/19*2/5*15/24 420/11400 = 7/190 In case 4 we have 8/20*7/19*15/25*10/24 = 2/5*7/19*3/5*5/12 = 210/5700 = 7/190 Probability of getting excatly one white will now become (84+84+35+35)/950 = 238/950 = 119/475 = 0.251 I hope this one is better now? =

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# A bag contains 7white, 6 red and 5 black balls. Two balls are drawn at random. Find the probability that they will both be white

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