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February 23rd, 2012, 09:16 PM  #1 
Joined: Feb 2012 Posts: 10 Thanks: 0  Probability problem.
Suppose that you are dealt a hand of 6 cards from a standard deck of 52 playing cards. a) What is the probability that you are dealt no jacks and exactly 1 diamond? b) What is the probability that you are dealt no more than 2 spades? c) What is the probability that you are dealt at least 2 sevens and at least 2 fives? 
February 24th, 2012, 01:30 AM  #2 
Joined: Oct 2011 From: Belgium Posts: 522 Thanks: 0  Re: Probability problem.
a) 
February 24th, 2012, 06:40 AM  #3  
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 2,854 Thanks: 164  Re: Probability problem. Hello, Ataloss! Quote:
[color=beige]. . [/color] [color=beige]. . [/color] [color=beige]. . [/color] Edit: corrected my typo. Quote:
There are four 7's, four 5's, and 44 Others. There are six case to consider. I'll let you finish up . . .  
February 24th, 2012, 08:41 AM  #4  
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 3,653 Thanks: 139  Re: Probability problem. Quote:
Thanks.  
February 24th, 2012, 04:40 PM  #5  
Joined: Dec 2010 Posts: 7 Thanks: 0  Re: Probability problem. Quote:
There are four 7's, four 5's, and 44 Others. There are six case to consider. I'll let you finish up . . . [/quote:n6nvu1q1] this is really confusing, is it possible for you to write it in a different way?  
February 24th, 2012, 07:23 PM  #6  
Global Moderator Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 11,718 Thanks: 187 Math Focus: The calculus  Re: Probability problem. Quote:
Quote:
You will be hard pressed to find anyone whose explanations are more clear and thorough.  
February 24th, 2012, 10:31 PM  #7  
Joined: Dec 2010 Posts: 7 Thanks: 0  Re: Probability problem. [/size] Edit: corrected my typo. Quote:
There are four 7's, four 5's, and 44 Others. There are six case to consider. I'll let you finish up . . . [/quote] How do you solve this? I am not familair with this level of probability.  

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