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October 29th, 2007, 09:38 PM  #1 
Newbie Joined: Oct 2007 Posts: 4 Thanks: 0  I hope this is in the right forum
Hey guys I am a newcomer and haven't played around with mathematics for a little while but this question seems to fit in here (from reading the description anyway). My friend gave me this puzzle and I have absolutley no idea how to figure it out. I have been given the numbers 17 which have a complementary greek letter from AlphaEta (alpha, beta, gamma, delta, epsilon, zeta, eta). He has told me that the number 4's complementary letter is Alpha, while the letter Delta is the complementary to the number 5 so it would be the following: 1234567 ###AD## So my question is, how would I figure out what 1, 2, 3, 6 and 7's complementary Greek letter? I am absolutley puzzled, any help would be fantastic. Thanks 
October 30th, 2007, 04:19 AM  #2  
Global Moderator Joined: Nov 2006 From: UTC 5 Posts: 16,046 Thanks: 938 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms  Re: I hope this is in the right forum Quote:
 
October 30th, 2007, 04:42 AM  #3 
Newbie Joined: Oct 2007 Posts: 4 Thanks: 0 
Well I tried a few things and all came out with different outputs (some were different anyway). At first I laid out 17 and labeled the number 4 (Alpha) as the 'middle' of the problem with its number also playing an important role in what I started. So with the number 4 already taken out of the problem I was left with 1, 2, 3, 5, 6, 7. With this I used the number 4 to count across the numbers path, skipping the number 4 as it had been matched already so I arrived at the number 5 which was labeled delta. So I continued with this and ended up getting a complete obscure outcome, only just realizing that if I were to use this method I would have had to start with Beta after Alpha, not Delta so I scrapped it. I used the Alpha as the start of my next method and figured I would use the number 4 as the start of my problem solving (This might be hard to explain but I will try my hardest!). So I laid out the following: Alpha Beta Gamma Delta Epsilon Zeta Eta Now I know Alpha equals 4 but I wanted to know what the rest of the numbers were (whilst proving why Delta = 5) so I counted 4 from Alpha on the list. Alpha, Beta, Gamma, DELTA. The number after 4 is 5 so I then labeled Delta as 5. After this I counted five down the list, going back to the top once at the end of the list. Delta, Epsilon, Zeta, Eta, (SKIP Alpha because it has been used), BETA. So I labeled Beta as number 6. From there I counted 6, skipping those greek letters than had already been used on the list and I got Gamma which equaled 7. Then I counted 7 down the list and labeled Epsilon as number 1, and continued so in the end I had the following result: Alpha = 04 Beta = 06 Gamma = 07 Delta = 05 Epsilon = 01 Zeta = 02 Eta 03 ABGDEpZE 4675123 It could be correct, I tried using logic and this seemed to be the most logical output. What do you guys think? 
October 30th, 2007, 05:14 AM  #4  
Global Moderator Joined: Nov 2006 From: UTC 5 Posts: 16,046 Thanks: 938 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms  Quote:
 
November 1st, 2007, 11:37 PM  #5 
Global Moderator Joined: Dec 2006 Posts: 20,746 Thanks: 2133 
This isn't the right forum for your question; since it obviously can't be resolved mathematically, it doesn't really belong anywhere here.


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