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January 29th, 2010, 05:40 AM   #1
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Calculate the number of even numbers between 5000 and 7000 which can be formed from the digits 1,5,6 and 8 if repetitions are allowed.
I tried working on this question and came to 48 but, the answer given is 60. Can anyone help me??? Thank you!
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January 29th, 2010, 07:16 AM   #2
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Originally Posted by cyt_91
Calculate the number of even numbers between 5000 and 7000 which can be formed from the digits 1,5,6 and 8 if repetitions are allowed.
The first digit must be 5 or 6. What can the second digit be? What can the third be? What can the fourth be? Multiply the number of possibilities for each digit.

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Originally Posted by cyt_91
I tried working on this question and came to 48 but, the answer given is 60.
Both 48 and 60 are wrong.
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