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July 2nd, 2015, 07:41 PM  #1 
Newbie Joined: Jul 2015 From: United States Posts: 2 Thanks: 0  Working towards being accepted into my computer programming major but bad at math.
I finished my second semester of college two months ago and during the second semester, I had problems with passing math class. That was my second semester being in math class. I am trying to learn math so I can get accepted into my computer programming major. I passed my writing classes but I cannot seem to pass math class. I am in basic math class. The math concept that keeps giving me problems each semester is fractions. Even though I am passing my other classes, I feel like I am not making progress towards being accepted into my major because math is a part of computer programming. Also, I was told by my college that there is a certain amount of times I can retake math class.

July 2nd, 2015, 08:43 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 18,689 Thanks: 1522 
Can you give an example of a specific thing that seemed difficult?

July 2nd, 2015, 10:49 PM  #3 
Newbie Joined: Jul 2015 From: United States Posts: 2 Thanks: 0 
skipjack, I know how to turn improper fractions into mixed numbers and turn mixed numbers into improper fractions but I am having problems trying to complete an addition of fractions problem that has unlike denominators and has a first fraction that is bigger than the second fraction (example: 17/100 + 10/10). I am having problems remembering how to add, subtract, multiply, and divide fractions. Over the summer break, I have been staying up all night watching videos on Khan Academy trying to learn math and I couldn't find any tutorials on the internet for how to add a fraction with unlike denominators that has a first fraction that is bigger than the second fraction. In my second semester in college, I tried math books but I did not have any success with the math books. My professors taught math at a fast pace and did not teach math in a step by step format. I was good at math until I went to high school. Sorry if I made a mistake when I was typing this reply. This is my first time using a forum. I am a social media user.

July 5th, 2015, 05:42 PM  #4 
Senior Member Joined: Oct 2013 From: New York, USA Posts: 590 Thanks: 81 
Which fraction is greater doesn't matter when computing them. Here are examples for each operation: Multiplication: 2/5 * 3/8 = 6/40 = 3/20 Multiply the numerators and multiply the denominators. Then reduce the fraction to lowest terms if necessary by dividing by the greatest common factor (GCF). The greatest common factor of 6 and 40 is 2. Division: (2/5)/(3/8) = 2/5 * 8/3 = 16/15 = 1 1/15 Multiply the first fraction by the reciprocal of the second fraction. In this case the answer is an improper fraction in lowest terms. Addition: 2/5 + 3/8 = 16/40 + 15/40 = 31/40 Subtraction: 2/5  3/8 = 16/40  15/40 = 1/40 Addition and subtraction require a common denominator. One way is to find the least common multiple (LCM) of the denominators. If you don't know how to do that, you can just multiply the denominators and use the product as a common denominator. In this case the least common multiple is the product of the denominators because there are no numbers greater than 1 that are factors of 5 and 8. To keep the value of a fraction, multiply the numerator and the denominator by whatever number is necessary to get a common denominator. Once you discover that you have 2/5 and need a common denominator of 40, multiply 2 and 5 by 8 to get 16/40. Another way of explaining it is the algebraic equation 2/5 = X/40. Crossmultiplying results in 5X = 80 and X = 16. 

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accepted, bad, bad at math, college, computer, computer programming, major, math, programming, working 
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