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October 3rd, 2009, 07:35 PM  #1 
Newbie Joined: Oct 2009 Posts: 14 Thanks: 0  Subgroup/Normal Subgroup/Automorphism Questions
In this problem, assume (important!) that G is an Abelian. Set H = {g in G : g^5 = e}. (Warning: Expressions such as x^1/5 are not well defined. Do not use them!) (a) Show H is a subgroup of G. (b) Show H is a normal subgroup of G. (c) Assume further that G is finite and that H = {e}. Show that the map phi : G > G given by phi(g) = g^5 is an automorphism. (Definition: An automorphism is an isomorphism from a group to itself.) 
October 4th, 2009, 04:12 AM  #2  
Senior Member Joined: Oct 2007 From: Chicago Posts: 1,701 Thanks: 3  Re: Subgroup/Normal Subgroup/Automorphism Questions Quote:
Quote:
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If not, show it is injective: show that a?b > phi(a)?phi(b). An injective function from A>A must be bijective for any finite set A. Cheers.  
October 4th, 2009, 09:14 PM  #3  
Newbie Joined: Oct 2009 Posts: 14 Thanks: 0  Re: Subgroup/Normal Subgroup/Automorphism Questions Quote:
If not, show it is injective: show that a?b > phi(a)?phi(b). An injective function from A>A must be bijective for any finite set A. Cheers.[/quote:16v4wr01] concerning part c... we've learned about homomorphisms. isn't the kernel of phi = e or something like that? i don't really know how to even begin showing part c.  
October 4th, 2009, 11:37 PM  #4 
Senior Member Joined: Oct 2007 From: Chicago Posts: 1,701 Thanks: 3  Re: Subgroup/Normal Subgroup/Automorphism Questions
The kernel is the set of elements which map to e. You should have learned that a homomorphism is n1: every element in the range has the same number (n) of elements map to it. If you can show that only one element maps to e, then you have a 11, homomorphism. And since the sets are finite and the same size, this is a bijective homomorphism an isomorphism. 

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