
Abstract Algebra Abstract Algebra Math Forum 
 LinkBack  Thread Tools  Display Modes 
February 15th, 2009, 04:44 PM  #1 
Newbie Joined: Feb 2009 Posts: 1 Thanks: 0  Find a abelian subgroup of S5 of order 6
Hi everyone! I'm trying to solve the above problem and have hit a wall! So far I know the identity is in the subgroup, two elements that commute and their inverses. I have the subgroup as: {(5),(4,5),(1,2,3),(1,3,2) What would the other two elements be? I've had someone tell me that if I multiply some of these elements together I'll get the other two, but every attempt I make, I always end up with elements I already have!!! If someone could show me what I need to do and if possible the solution to the above problem I'd appreciate it! Thanks~ 
February 16th, 2009, 07:05 AM  #2 
Senior Member Joined: Nov 2008 Posts: 199 Thanks: 0  Re: Find a abelian subgroup of S5 of order 6
Do you understand how permutations multiply? For example,(1,2,3)(4,5) is trivially a permutation distinct from the ones you list as it does a different thing to the set {1,2,3,4,5} from any of the others.


Tags 
abelian, find, order, subgroup 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Proof that group of order 2k containts order k subgroup  Kappie  Abstract Algebra  0  April 22nd, 2012 01:52 PM 
Show group with order 595 is abelian.  watson  Abstract Algebra  4  December 20th, 2011 12:18 PM 
H is a subgroup of its Centralizer iff H is Abelian  xsw001  Abstract Algebra  5  February 16th, 2011 02:00 AM 
Find the order of the cyclic subgroup of D2n generated by r  xsw001  Abstract Algebra  0  February 3rd, 2011 05:54 PM 
Subgroup of Abelian Group  LoveOneAnother  Abstract Algebra  1  November 7th, 2010 04:37 AM 