My Math Forum Find a abelian subgroup of S5 of order 6

 Abstract Algebra Abstract Algebra Math Forum

 February 15th, 2009, 04:44 PM #1 Newbie   Joined: Feb 2009 Posts: 1 Thanks: 0 Find a abelian subgroup of S5 of order 6 Hi everyone! I'm trying to solve the above problem and have hit a wall! So far I know the identity is in the subgroup, two elements that commute and their inverses. I have the subgroup as: {(5),(4,5),(1,2,3),(1,3,2) What would the other two elements be? I've had someone tell me that if I multiply some of these elements together I'll get the other two, but every attempt I make, I always end up with elements I already have!!! If someone could show me what I need to do and if possible the solution to the above problem I'd appreciate it! Thanks~
 February 16th, 2009, 07:05 AM #2 Senior Member   Joined: Nov 2008 Posts: 199 Thanks: 0 Re: Find a abelian subgroup of S5 of order 6 Do you understand how permutations multiply? For example,(1,2,3)(4,5) is trivially a permutation distinct from the ones you list as it does a different thing to the set {1,2,3,4,5} from any of the others.

 Tags abelian, find, order, subgroup

,
,

,

,

,

,

,

,

,

,

,

# how to find the number of elements of order 6 in s5?

Click on a term to search for related topics.
 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post Kappie Abstract Algebra 0 April 22nd, 2012 01:52 PM watson Abstract Algebra 4 December 20th, 2011 12:18 PM xsw001 Abstract Algebra 5 February 16th, 2011 02:00 AM xsw001 Abstract Algebra 0 February 3rd, 2011 05:54 PM LoveOneAnother Abstract Algebra 1 November 7th, 2010 04:37 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top