My Math Forum Order of an element in a Group

 Abstract Algebra Abstract Algebra Math Forum

 January 15th, 2018, 03:11 AM #1 Senior Member   Joined: Nov 2015 From: hyderabad Posts: 232 Thanks: 2 Order of an element in a Group Q : An element 'a' in a group has order 100. Then what is the order of a^65 ? Property : if o(a) = n & p is prime to n then o(a^p) = n. Using the above property, removing common factors between 65 & 100, we get 13 & 20. Then o(a^65) would be 20 ? I just tried let me know how to solve above question if it's wrong. Thanks
 January 17th, 2018, 03:44 AM #2 Member     Joined: Aug 2011 From: Nouakchott, Mauritania Posts: 85 Thanks: 14 Math Focus: Algebra, Cryptography Good morning. Yes, your answer is correct. It is a result of the following property, which generalizes the one you mentioned in your post: Let $\displaystyle o(a)=n$ and let $\displaystyle m\in{\mathbb N}$. Then $\displaystyle o\left(a^m\right)=\dfrac nd$, where $\displaystyle d=\gcd(n,m)$. Last edited by skipjack; January 17th, 2018 at 05:52 PM.
 January 17th, 2018, 03:57 AM #3 Senior Member   Joined: Nov 2015 From: hyderabad Posts: 232 Thanks: 2 Thank you so much for the response. Last edited by skipjack; January 17th, 2018 at 05:53 PM.
 January 17th, 2018, 10:09 AM #4 Member   Joined: Jan 2016 From: Athens, OH Posts: 92 Thanks: 47 Ould Yubba has given you the correct formula. The proof is straight forward:

 Tags element, group, order

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post Eispin Number Theory 2 September 20th, 2017 05:20 PM stf92 Abstract Algebra 1 July 6th, 2017 10:07 AM cummings123 Abstract Algebra 1 February 3rd, 2013 11:23 AM Watari Abstract Algebra 2 December 13th, 2012 06:59 PM DLowry Abstract Algebra 2 April 25th, 2011 11:43 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top