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 faker97 April 21st, 2017 08:21 AM

Equivalence relation, complex numbers

https://gyazo.com/c0663bbc6abe1224ba5ea32de4568cec Any ideas on how to progress with this? Do you cube and add 2pi to the arguments? For the second part is it acceptable to rewrite -2 in exponential form and then continue from there? Thanks

 Maschke April 21st, 2017 09:16 AM

Quote:
 Originally Posted by faker97 (Post 568012) https://gyazo.com/c0663bbc6abe1224ba5ea32de4568cec Any ideas on how to progress with this? Do you cube and add 2pi to the arguments? For the second part is it acceptable to rewrite -2 in exponential form and then continue from there? Thanks
Hint: $1 \sim e^{\frac{2\pi}{3}} \sim e^{\frac{4\pi}{3}}$.

 faker97 April 21st, 2017 09:49 AM

Thanks for the reply. So for e^(ipi/4) you would get e^(11pi/12), e^(19pi/12) and so on?

 Maschke April 21st, 2017 11:35 AM

Hint on the other one. Why doesn't the idea of rotations work with ${-2}$?

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