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Lalitha183 March 29th, 2017 06:45 PM

Equivalence Relations
 
1 Attachment(s)
Hello All.
Anyone please help me to understand the step marked in the image.
Thanks for your help 😊

romsek March 29th, 2017 09:26 PM

$\dfrac{d}{dx}~(c_1-c_2)=0$

Lalitha183 March 29th, 2017 09:38 PM

Quote:

Originally Posted by romsek (Post 565683)
$\dfrac{d}{dx}~(c_1-c_2)=0$


Ah thank you. I forgot that the differentiation of constant is zero.
Thanks for reminding me 😊


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