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 December 6th, 2016, 12:43 PM #1 Newbie   Joined: Dec 2016 From: Vietnam Posts: 2 Thanks: 0 Condition of inequation I have two sets of numbers satisfying: x1+x2+...+xn>=y1+y2+...+yn Whether it is the case: x1^2+x2^2+...+xn^2>=y1^2+y2^2+...+yn^2 (xi^2 presents the square of xi). xi,yi here are not negative numbers.
 December 6th, 2016, 02:40 PM #2 Global Moderator   Joined: May 2007 Posts: 6,823 Thanks: 723 Proof by mathematical induction. Assuming you want to prove it for all n. x1>y1 implies x1^2>y1^2 x2>y2 implies x2^2>y2^2 Add together and get x1+x2>y1+y2 implies x1^2+x2^2>y1^2+y2^2
 December 7th, 2016, 01:45 AM #3 Newbie   Joined: Dec 2016 From: Vietnam Posts: 2 Thanks: 0 What do you think about: 3+1>=2+2 3^2+1^2>=2^2+2^2
 December 7th, 2016, 01:45 PM #4 Global Moderator   Joined: May 2007 Posts: 6,823 Thanks: 723 2+2>3+0 4+4<9+0

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