
Abstract Algebra Abstract Algebra Math Forum 
 LinkBack  Thread Tools  Display Modes 
December 6th, 2016, 12:43 PM  #1 
Newbie Joined: Dec 2016 From: Vietnam Posts: 2 Thanks: 0  Condition of inequation
I have two sets of numbers satisfying: x1+x2+...+xn>=y1+y2+...+yn Whether it is the case: x1^2+x2^2+...+xn^2>=y1^2+y2^2+...+yn^2 (xi^2 presents the square of xi). xi,yi here are not negative numbers. 
December 6th, 2016, 02:40 PM  #2 
Global Moderator Joined: May 2007 Posts: 6,276 Thanks: 516 
Proof by mathematical induction. Assuming you want to prove it for all n. x1>y1 implies x1^2>y1^2 x2>y2 implies x2^2>y2^2 Add together and get x1+x2>y1+y2 implies x1^2+x2^2>y1^2+y2^2 
December 7th, 2016, 01:45 AM  #3 
Newbie Joined: Dec 2016 From: Vietnam Posts: 2 Thanks: 0 
What do you think about: 3+1>=2+2 3^2+1^2>=2^2+2^2 
December 7th, 2016, 01:45 PM  #4 
Global Moderator Joined: May 2007 Posts: 6,276 Thanks: 516 
2+2>3+0 4+4<9+0 

Tags 
condition, inequation 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Inequation  Dang  Elementary Math  5  December 30th, 2013 03:58 PM 
inequation  metalari  Algebra  1  December 2nd, 2012 02:47 AM 
Inequation  msambinelli  Applied Math  5  April 1st, 2012 07:48 AM 
inequation  kapital  Elementary Math  6  December 29th, 2010 10:39 PM 
Inequation  Alvy  Calculus  3  March 27th, 2010 07:32 AM 