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May 1st, 2016, 08:33 AM  #1 
Newbie Joined: Jan 2016 From: Naples Posts: 4 Thanks: 0  Simplifying this Boolean expression
This is the function: $(x + y)(x' + z)$ I did this: $(x + y)(x' + z) = $ $xx' + xz + x'y + yz = $ $xz + x'y + yz = $ $x(y + y')z + x'y(z + z') + (x + x')yz = $ $xyz + xy'z + x'yz + x'yz' + xyz + x'yz = $ $xyz + xy'z + x'yz + x'yz' + x'yz = $ $xy'z + x'y(z + z') + (x + x')yz = $ $xy'z + x'y + yz$ Is this correct? Was there a better and faster way to do it? 
May 1st, 2016, 08:54 AM  #2 
Newbie Joined: May 2016 From: Kolkata Posts: 1 Thanks: 1 
I think the steps are correct uptil 3rd step , no need to drag along the process after that ! Its a sum relating to simplification and not proof ! 
May 1st, 2016, 02:04 PM  #3 
Senior Member Joined: Feb 2016 From: Australia Posts: 1,834 Thanks: 650 Math Focus: Yet to find out. 
It depends what you are trying to do, as hellosuman has said. Do you need to simplify, or convert your POS expression into a SOP expression?


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boolean, expression, simplifying 
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