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November 8th, 2011, 01:20 AM   #1
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subgroup

Let H be a subgroup of G and . Then prove:

.

Does anyone know how to solve or can give any clue?
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November 8th, 2011, 01:24 AM   #2
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Re: subgroup

There should be:
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November 10th, 2011, 09:08 AM   #3
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Re: subgroup

IS not true that for all g from G g*g is at H,
let suppose that G/H is a group and
G/H={xH,H } ,since G/H is group and H is zero of G?H we have
that x*h is at (xH)(H)=xH so is not at H ,and h at H and we have
xh isnot at H ! ,so your question is incorrect.
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