My Math Forum Herstein: Abstract Algebra Proof (Sylow's Theorem)

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 November 3rd, 2011, 07:05 PM #1 Newbie   Joined: Oct 2011 Posts: 2 Thanks: 0 Herstein: Abstract Algebra Proof (Sylow's Theorem) if P^m divides |G|, show that G has a subgroup of order P^m
 November 11th, 2011, 05:25 AM #2 Member   Joined: Jun 2010 Posts: 64 Thanks: 0 Re: Herstein: Abstract Algebra Proof (Sylow's Theorem) We have to solve it by sylow theorem, P^m divides |G| then we have that p||G|,so exist an integer n such that P^n| |G| and n is the greatest integer that P^n||G|, By the sylow theorem exist a subgroup H

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